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26. If the roots of the equations ax² + 2bx + c = 0 and bx² – 2√ac x + b = 0 are simultaneously real, then (a) b = ac (b) b2 = ac (c) a2 = be (d) c2 = ab

26. If the roots of the equations ax² + 2bx + c = 0 and bx² – 2√ac x + b = 0 are simultaneously real, then
(a) b = ac
(b) b2 = ac
(c) a2 = be
(d) c2 = ab

Grade:12th pass

1 Answers

Pawan Prajapati
askIITians Faculty 8740 Points
3 months ago
Answer: b Explaination:Reason: Given equations have real roots, then D1 ≥ 0 and D2 ≥ 0 (2b)² – 4ac > 0 and (-2√ac)² – 4b.b ≥ 0 4b² – 4ac ≥ 0 and 4ac – 4b2 > 0 b² ≥ ac and ac ≥ b² ⇒ b² = ac

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