25. If -5 is a root of the quadratic equation 2x² + px – 15 = 0, then
(a) p = 3
(b) p = 5
(c) p = 7
(d) p = 1

Question

25. If -5 is a root of the quadratic equation 2x² + px – 15 = 0, then (a) p = 3 (b) p = 5 (c) p = 7 (d) p = 1

Pawan Prajapati · Answer

Answer: c Explaination:Reason: Since – 5 is a root of the equation 2x² + px -15 = 0 ∴ 2(-5)² + p (-5) – 15 = 0 ⇒ 50 – 5p -15 = 0 ⇒ 5p = 35 ⇒ p = 7

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25. If -5 is a root of the quadratic equation 2x² + px – 15 = 0, then (a) p = 3 (b) p = 5 (c) p = 7 (d) p = 1

25. If -5 is a root of the quadratic equation 2x² + px – 15 = 0, then
(a) p = 3
(b) p = 5
(c) p = 7
(d) p = 1

1 Answers

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25. If -5 is a root of the quadratic equation 2x² + px – 15 = 0, then (a) p = 3 (b) p = 5 (c) p = 7 (d) p = 1

25. If -5 is a root of the quadratic equation 2x² + px – 15 = 0, then (a) p = 3 (b) p = 5 (c) p = 7 (d) p = 1

1 Answers

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25. If -5 is a root of the quadratic equation 2x² + px – 15 = 0, then
(a) p = 3
(b) p = 5
(c) p = 7
(d) p = 1