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13. Find the sum of first 15 multiples of 8.

Harshit Singh , 3 Years ago
Grade 12th pass
anser 1 Answers
Pawan Prajapati

Last Activity: 3 Years ago

The multiples of 8 are 8, 16, 24, 32… The series is in the form of AP, having first term as 8 and common difference as 8. Therefore, a = 8 d = 8 S15 = ? By the formula of sum of nth term, we know, Sn = n/2 [2a+(n-1)d] S15 = 15/2 [2(8) + (15-1)8] = 15/2[6 +(14)(8)] = 15/2[16 +112] = 15(128)/2 = 15 × 64 = 960

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