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`        1.3+3.5+5.7+....100terms find the value of this question `
6 months ago

```							Dear student 3 + 3.5 + 5.7 + ...... + (2r + 1)(2r + 3)+ ....upto n termsso, here it is clear that , and sum of n terms of series , = = we know, , means sum of square of natural number = n(n + 1)(2n + 1)/6and  means, sum of n times of 1 i.e., 1 + 1 + 1 + 1 + 1.... n terms = nthen, Sn = 4[ n(n + 1)(2n + 1)/6 ] - n= 2n(n + 1)(2n + 1)/3 - n= n [ (2n + 2)(2n + 1)/3 - 1]= n [ (4n² + 6n + 2) - 3 ]/3= n (4n² + 6n - 1)/3put n = 100 now = 100( 40599)/3 = 1353300
```
6 months ago
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