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  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
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The Syllabus for CET (B. Tech. & M. Tech. programs) for the subjects of Physics, Chemistry, Mathematics, Biology (Botany & Zoology) or Biotechnology is similar to the CBSE syllabus for class 11th and 12th of 10+2 pattern.


There will be 3 subjects in the Entrance Examination. The three subjects are:

  • Physics: 33.33%

  • Chemistry: 33.33%

  • Mathematics: 33.33%

  • The total duration of the CET will be 2½ Hours.
  • The Medium of the CET will be English.

  • There will be a total of 150 objective-type questions in the Entrance Examination. Each question will have 4 options and candidates have to choose only one option as the correct answer. Each question will carry four marks. For every incorrect answer, candidates will be marked negatively and consequently 1 mark will be deducted for the same.

  • The CET 2018 will carry 600 marks.

  • The result of the CET will be announced on the official website of the University ( on the given dates. 

Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution