{"id":2923,"date":"2014-04-08T19:13:52","date_gmt":"2014-04-08T13:43:52","guid":{"rendered":"https:\/\/www.askiitians.com\/blog\/?p=2923"},"modified":"2014-04-08T19:13:52","modified_gmt":"2014-04-08T13:43:52","slug":"calculation-percentile-normalization-marks-composite-score","status":"publish","type":"post","link":"https:\/\/www.askiitians.com\/blog\/calculation-percentile-normalization-marks-composite-score\/","title":{"rendered":"Calculation of percentile, normalization of marks and Composite score"},"content":{"rendered":"

\"calculator-and-numbers_opt\"<\/a>Percentile<\/strong><\/em><\/p>\n

Difference between Percentage & Percentile & calculation of percentile:<\/p>\n

Percentage<\/b>: As you all know percentage is a number out of 100.Percentage marks = (Obtained marks \/ Total marks) \u00c3\u0192\u00e2\u20ac\u201d100<\/p>\n

Percentile:<\/b>Percentile score of a candidate reflects the number of students who have scored below that student in his\/her own Board ( CBSE, ICSE etc..)
\nExample:<\/b>In a particular board 4000 candidates appeared in the examination.If a candidate obtained 70 % marks and 2000 students have scored below 70%, then the percentile of that student = (2000\u00c3\u0192\u00e2\u20ac\u201d100)\/4000 = 50.0<\/p>\n

Normalization of marks<\/strong><\/em><\/p>\n

Step 1:
\n<\/b>Calculate percentile (P) of all the candidate of board XYZ who are eligible for the JEE (Main) exam<\/a>, with reference to their board result.
\nFor a Board XYZ
\nTotal Number of the candidates appearing in board exam = 4000<\/p>\n\n\n\n\n\n\n\n\n
\n

Marks of candidates in Board Exam<\/p>\n

(m)<\/p>\n<\/td>\n

\n

Number of candidates who scored below the candidate (m)<\/p>\n<\/td>\n

\n

Percentile Calculation<\/p>\n<\/td>\n

\n

Percentile (p1<\/sub>)<\/p>\n<\/td>\n<\/tr>\n

\n

50%<\/p>\n<\/td>\n

\n

1500<\/p>\n<\/td>\n

\n

(1500\/4000)\u00c3\u0192\u00e2\u20ac\u201d100<\/p>\n<\/td>\n

\n

37.5<\/p>\n<\/td>\n<\/tr>\n

\n

60%<\/p>\n<\/td>\n

\n

1700<\/p>\n<\/td>\n

\n

(1700\/4000)\u00c3\u0192\u00e2\u20ac\u201d100<\/p>\n<\/td>\n

\n

42.5<\/p>\n<\/td>\n<\/tr>\n

\n

70%<\/p>\n<\/td>\n

\n

2000<\/p>\n<\/td>\n

\n

(2000\/4000)\u00c3\u0192\u00e2\u20ac\u201d100<\/p>\n<\/td>\n

\n

50.0<\/p>\n<\/td>\n<\/tr>\n

\n

80%<\/p>\n<\/td>\n

\n

2500<\/p>\n<\/td>\n

\n

(2500\/4000)\u00c3\u0192\u00e2\u20ac\u201d100<\/p>\n<\/td>\n

\n

62.5<\/p>\n<\/td>\n<\/tr>\n

\n

90%<\/p>\n<\/td>\n

\n

3500<\/p>\n<\/td>\n

\n

(3500\/4000)\u00c3\u0192\u00e2\u20ac\u201d100<\/p>\n<\/td>\n

\n

87.5<\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

Step:2
\n<\/b>In the same way calculate the percentile of all the candidates with reference to their JEE main score.
\nLet total number of the candidates appearing in JEE (Main) exam = 1000000<\/p>\n\n\n\n\n\n\n\n\n
\n

JEE(Main) Score<\/p>\n

(n)<\/p>\n<\/td>\n

\n

Number of candidates below the candidate with JEE (Main) score (n)<\/p>\n<\/td>\n

\n

Percentile Calculation<\/p>\n<\/td>\n

\n

Percentile (p2<\/sub>)<\/p>\n<\/td>\n<\/tr>\n

\n

75<\/p>\n<\/td>\n

\n

500000<\/p>\n<\/td>\n

\n

(500000\/1000000)\u00c3\u0192\u00e2\u20ac\u201d100<\/p>\n<\/td>\n

\n

50.0<\/p>\n<\/td>\n<\/tr>\n

\n

100<\/p>\n<\/td>\n

\n

600000<\/p>\n<\/td>\n

\n

(600000\/1000000)\u00c3\u0192\u00e2\u20ac\u201d100<\/p>\n<\/td>\n

\n

60.0<\/p>\n<\/td>\n<\/tr>\n

\n

150<\/p>\n<\/td>\n

\n

700000<\/p>\n<\/td>\n

\n

(700000\/1000000)\u00c3\u0192\u00e2\u20ac\u201d100<\/p>\n<\/td>\n

\n

70.0<\/p>\n<\/td>\n<\/tr>\n

\n

200<\/p>\n<\/td>\n

\n

800000<\/p>\n<\/td>\n

\n

(800000\/1000000)\u00c3\u0192\u00e2\u20ac\u201d100<\/p>\n<\/td>\n

\n

80.0<\/p>\n<\/td>\n<\/tr>\n

\n

250<\/p>\n<\/td>\n

\n

900000<\/p>\n<\/td>\n

\n

(900000\/1000000)\u00c3\u0192\u00e2\u20ac\u201d100<\/b><\/p>\n<\/td>\n

\n

90.0<\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

\u00c3\u201a\u00c2\u00a0<\/b>Step: 3
\n<\/b>Use the value of percentile (P1<\/sub>) calculated in step 1 (Table 1) and find out the same value of percentile in the table 2 (step 2). The corresponding JEE (Main) score would represent value of B1<\/sub>.
\nIn our example the percentile of candidate with 70% board marks was 50.
\nSo in table 2, percentile 50.0 represents JEE (Main) score of 75. So, B1<\/sub> = 75.\u00c3\u201a\u00c2\u00a0<\/b><\/p>\n

Step:4
\n<\/b>Calculate the percentile of the candidates of the particular board (say XYZ ) who appeared in the JEE main with reference to their JEE main score.
\nNumber of the candidates of board xyz appeared in JEE main = 4000<\/p>\n\n\n\n\n\n\n\n\n
\n

JEE(Main) Score<\/p>\n

(n)<\/p>\n<\/td>\n

\n

Number of candidates below the candidate with JEE (Main) score (n)<\/p>\n<\/td>\n

\n

Percentile Calculation<\/p>\n<\/td>\n

\n

Percentile (p3<\/sub>)<\/p>\n<\/td>\n<\/tr>\n

\n

25<\/p>\n<\/td>\n

\n

1000<\/p>\n<\/td>\n

\n

(1000\/4000)\u00c3\u0192\u00e2\u20ac\u201d100<\/p>\n<\/td>\n

\n

25.0<\/p>\n<\/td>\n<\/tr>\n

\n

50<\/p>\n<\/td>\n

\n

1500<\/p>\n<\/td>\n

\n

(1500\/4000)\u00c3\u0192\u00e2\u20ac\u201d100<\/p>\n<\/td>\n

\n

37.5<\/p>\n<\/td>\n<\/tr>\n

\n

100<\/p>\n<\/td>\n

\n

2000<\/p>\n<\/td>\n

\n

(2000\/4000)\u00c3\u0192\u00e2\u20ac\u201d100<\/p>\n<\/td>\n

\n

50.0<\/p>\n<\/td>\n<\/tr>\n

\n

150<\/p>\n<\/td>\n

\n

3000<\/p>\n<\/td>\n

\n

(3000\/4000)\u00c3\u0192\u00e2\u20ac\u201d100<\/p>\n<\/td>\n

\n

75.0<\/p>\n<\/td>\n<\/tr>\n

\n

200<\/p>\n<\/td>\n

\n

3600<\/p>\n<\/td>\n

\n

(3600\/4000)\u00c3\u0192\u00e2\u20ac\u201d100<\/b><\/p>\n<\/td>\n

\n

90.0<\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

\u00c3\u201a\u00c2\u00a0<\/b>Step: 5
\n<\/b>Use the value of percentile (P1<\/sub>) calculated in step 1 (Table 1) and find out the same value in the table 3 (step 4). The corresponding JEE (Main) score would represent value of B2<\/sub>.
\nIn our example the percentile of candidate with 70% board marks was 50.
\nSo in table 3, percentile 50.0 represents JEE (Main) score of 100. So, B2<\/sub> = 100
\nStep: 6<\/b><\/p>\n

Bfinal<\/sub> = 0.5\u00c3\u0192\u00e2\u20ac\u201d (B1<\/sub>+B2<\/sub>)
\nIn our example:
\nB final<\/sub> = 0.5\u00c3\u0192\u00e2\u20ac\u201d (75 + 100) = 87.5
\nFor admission to CFTIs, it has been decided to use JEE Mains Marks (AO) and the normalized board marks(\u00c3\u0192\u00e2\u20ac\u201d B final<\/sub>)\u00c3\u201a\u00c2\u00a0 in 60:40 ratio.So,
\nComposite score for drawing the merit list (c ) = 0.6\u00c3\u0192\u00e2\u20ac\u201d AO + 0.4\u00c3\u0192\u00e2\u20ac\u201d B final
\n<\/sub>In our example:
\nc\u00c3\u201a\u00c2\u00a0 = 0.6\u00c3\u0192\u00e2\u20ac\u201d 75 + 0.4\u00c3\u0192\u00e2\u20ac\u201d 87.5 = 80.<\/p>\n

For getting your estimated rank in IIT JEE you can use our\u00c3\u201a\u00c2\u00a0 Rank Predictor<\/a><\/p>\n

\"Click<\/a>
\nThis post was published by Aditya Singhal<\/a>, co-founder of askIITians<\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":"

Percentile Difference between Percentage & Percentile & calculation of percentile: Percentage: As you all know percentage is a number out of 100.Percentage marks = (Obtained marks \/ Total marks) \u00c3\u0192\u00e2\u20ac\u201d100 Percentile:Percentile score of a candidate reflects the number of students who have scored below that student in his\/her own Board ( CBSE, ICSE etc..) Example:In […]<\/p>\n","protected":false},"author":2,"featured_media":2929,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[5],"tags":[],"class_list":["post-2923","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-engineering-exams"],"_links":{"self":[{"href":"https:\/\/www.askiitians.com\/blog\/wp-json\/wp\/v2\/posts\/2923","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.askiitians.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.askiitians.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.askiitians.com\/blog\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/www.askiitians.com\/blog\/wp-json\/wp\/v2\/comments?post=2923"}],"version-history":[{"count":0,"href":"https:\/\/www.askiitians.com\/blog\/wp-json\/wp\/v2\/posts\/2923\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.askiitians.com\/blog\/wp-json\/wp\/v2\/media\/2929"}],"wp:attachment":[{"href":"https:\/\/www.askiitians.com\/blog\/wp-json\/wp\/v2\/media?parent=2923"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.askiitians.com\/blog\/wp-json\/wp\/v2\/categories?post=2923"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.askiitians.com\/blog\/wp-json\/wp\/v2\/tags?post=2923"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}