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when jim and rob rides bicycle, jim can only accelarate at three quarters the accelaration of rob. both start from rest at the bottom of a long straight roadwith a constant uppward slope. if rob takes 5 mins to reach the top, how much earlier should jim start to reach the top at the same time as rob?
let d be distance, acceleration of jim=a
d=(1/2)(4a/3)(5min)2
let t be time for jim
d=(1/2)(a)(t)2
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