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Revision Notes on Parabola
The general equation of a conic is ax2 + 2hxy + by2 + 2gx + 2fy +c =0. Here if e =1 and D≠ 0, then it represents a parabola.
The general equation of parabola is (y-y0)2 = (x-x0), which has its vertex at (x0, y0).
The general equation of parabola with vertex at (0, 0) is given by y2 = 4ax, and it opens rightwards.
The parabolax2 = 4ay opens upwards.
The equation y2 = 4ax is considered to be the standard equation of the parabola for which the various components are
Vertex at (0,0)
Directrix is x+a = 0
Axis is y = 0
Focus is (a, 0)
Length of latus rectum = 4a
Ends of latus rectum are L(a, 2a) and L’(a, -2a)
The parabola y = a(x – h)2 + khas its vertex at (h, k)
The perpendicular distance from focus on directrix is half the length of latus rectum
Vertex is the middle point of the focus and the point of intersection of directrix and axis
Two parabolas are said to be equal if they have the same latus rectum
The point (x1, y1) lies outside, on or inside the parabolay2 = 4ax, according as the expression y12 = 4ax1 is positive, zero or negative.
Length of the chord intercepted by the parabola on the line y = mx + c is (4/m2) √a(1+m2) (a-mc)
Length of the focal chord which makes an angle δ with the x-axis is 4a cosec2δ
In parametric form, the parabola is represented by the equations x = at2 and y =2at
The equation of a chord joining t1 and t2 is given by 2x – (t1 + t2) y + 2at1t2 = 0
If a chord joining t1, t2 and t3, t4 pass through a point (c, 0) on the axis, then t1t2 = t3t4 = -c/a
Tangents to the parabola y2 = 4ax
yy1 = 2a(x+x1) at the point (x1, y1)
y = mx + a/m ( m ≠ 0) at (a/m2, 2a/m)
ty = x+at2 at (at2, 2at)
Normals to the parabola y2 = 4ax
y-y1 = -y1/ 2a(x-x1) at the point (x1, y1)
y = mx -2am – am3 at (am2, -2am)
y + tx = 2at +at3 at (at2, 2at)
The equation of the director circle to the parabola is x + a = 0 which is same as the equation...
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Solved Examples on Parabola Illustration 1: If x +...