MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,000
  • View Details

Solved Examples on Transition Elements:

Question:1, Ti(H2O)6]3+ is coloured whereas  [Sc(H­2O)6]3+ is colourless, though it is a transition metal complex. Explain the observation.

Solution: Ti3+ has one electron in the d-orbital (3d1) which can absorb energy corresponding to yellow wavelength and jump from lower energy level to higher energy level. But Sc3+ has no electron in d-orbital.

Get Chapter Test for this Topic

Question: 2, NiCl4]2– is paramagnetic while (Ni(CO)4] is diamagnetic. Why?

Solution: In [Ni(CO)4], Ni is in zero oxidation state whereas is (NiCl4]2–, Ni is in +2 oxidation state. In the presence of ligand CO, the unpaired electrons of Ni pair up but Cl being a weak ligand is unable to pair up the unpaired electrons.

Question:3, Calculate the magnetic moment of V3+.

Solution: The electronic configuration of V3+ is [Ar] 4s°3d2. In the d–orbitals there are 2 unpaired electrons 

Question:4, Why Sm2+, Eu2+ and Yb2+ ions in solutions are good reducing agents but an aqueous solution of Ce4+ is a good oxidizing agent?

Solution: The most stable oxidation state of lanthanides is +3 hence ions in +2 state tend to change to +3 state by loss of electron and those in+4 state tend to change to +3 state by gain of electron

  • Complete AIPMT/AIIMS Course and Test Series
  • OFFERED PRICE: Rs. 15,000
  • View Details