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CHEMISTRY SECTION – II PART – A Straight Objective Type: This section contains 9 multiple choice questions numbered 1 to 9. Each question has 4 choices (A), (B), (C) and (D), out of which ONLY ONE is correct. 1. At what molar concentration of HCI will its aqueous solution have an [H+] to which equal contribution come from HCI and H2O at 900C. [Kw of H2O = 10–12M2 at 900C] (A) √50 × 10–8 (B) √40 × 10–7 M (C) √50 × 10–7 (D) √30 × 10–7 2. 100 ml of 0.5 M hydrazoic acid (N3H Ka = 3.6 × 10–4 ) and 400 ml of 0.1 M cyanic acid (HOCN1 Ka = 8 × 10–4) are mixed. Which of the following is true for final solution? (A) [H+ ] = 2 × 10–2 M (B) [N3– ] 3.6 × 10–2 M (C) [OCN– ] = 4.571 × 10–3 M (D) [OCN– ] = 6.4 × 10–3 M 3. Adding a few drops of hydrochloric acid to a beaker containing water results in the formation of hydrated species. Identify which hydrated species can exist in solution (1) H3O+ (2) H3O2+ (3) H5O2+ (4) H2CIO– (A) 1 only (B) 1 and 2 (3) 1, 2 and 3 (4) 1, 2, 3 and 4 4. Identify the incorrect statement regarding inter-halogen compounds CIF3 and FCI3. (A) FCI3 is not possible as F does not have vacant d-orbitals to allow octet-expansion. (B) All bond lengths in CIF3 are not identical. (C) CIF3 has umbrella shaped geometry. (D) F – CI – F bond angle is 900. Aspirin is a pain reliever with pKa = 2. Two tablets each containing 0.09 gm of aspirin are dissolved in 100 ml solution. The restaurant pH is (A) 0.5 (B) 1.1 (C) 2.2 (D) 3.5 6. The vapour density of completely dissociated NH4CI would be (A) half that of NH4CI(g) (B) less than half that of NH4CI (C) more than half that of NH4CI (D) depends on amount of NH4CI taken at start 7. In the unbalanced reaction : AI + KMnO4 + H2SO4 ® KHSO4 + AI2 (SO4)3 + MnSO4 + H2O If the stoichiometric coefficients of AI, H2SO4, MnSO4 and H2O are w, x, y and z respectively, the numerical value of (x/y-z/w) will be (A) 2.0 (B) 2.1 (C) 1.2 (D) 2.4 8. Which of the features of an tom is not a direct result of Rutherford’s experiment? (A) extra ordinary hollow nature of atom (B) existence of circular electronic orbits (C) small size of the nucleus (D) exceptionally high density of nuclear material 9. If electrons were to fill up progressively with orbit saturation (neglecting Auf Bau rule) and each orbital were to accommodate three electrons, instead of two; which of the following would NOT hold correct for the new electronic arrangement in Zirconium atom (Z = 40)? (A) the number of p-electrons would be double the number of s-electrons (B) spin quantum number would become super flows (C) Zirconium would continue to belong to the 4th period (in new periodic table) (D) Zirconium would show retention of block ASSERTION - REASON TYPE This contains 4 questions numbered 10 to 13. Each question contains STATEMENT-1 (Assertion) and STATEMENT-2 (Reason). Each question has 4 choices (A), (B), (C) and (D) out of which ONLY ONE is correct. 10. STATEMENT-1 : Le Chatliers principle is not applicable to Fe(s) + S(s) ? FeS(s) STATEMTN-2 : Le Chatliers principle aims to push the reaction into stress – free environment. (A) Statement-1 is True, statement-2 is True; Statement-2 is a correct explanation for Statement-1. (B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1. (C) Statement-1 is True, Statement-2 is False. (D) Statement-1 is False, statement-2 is True. 11. STATEMENT-1 : Passing H2 gas through a muddy solution of ferric chloride result in colour change. because STATEMENT-2 : H2 is a reducing agent. (A) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1. (B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1. (C) Statement-1 is True, Statement-2 is False. (D) Statement- is False, Statement-2 is True. 12. STATEMENT-1 : A bowler bowling the last crucial over in an India – Pakistan 20-20 match breathes heavily due to excitement and tension, leading to significant change in the pH of blood. because STATEMENT-2 : pH of blood = pKa + log [HCO3- ]/[H2 CO3 ] (A) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1. (B) Statement-1 is True, Statement-2 is True; statement-2 is NOT a correct explanation for Statement-1. (C) Statement-1 is True, Statement-2 is False. (D) Statement-1 is False, Statement-2 is True. 13. STATEMENT-1 : Agl is yellow and more soluble than Ag2S in water. because STATEMENT-2 : Agl shows colour due to d – d transition and is more soluble as it is more covalent. (A) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1. (B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1. (C) Statement-1 is True, Statement-2 is False. (D) Statement-1 is False, Statement-2 is True.
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