All You Wanted to Know about the Normalization Procedure

Since 2013, admission to NITs (National Institutes of Technology) and several other centrally-funded technical institutes is based on the scores of both the entrance exam and Class 12 Board marks. According to the notification of JEE Main 2013, 40% importance will be given to Board marks (top 5 subjects). Considering the large-scale variations across different examination systems in the country, the JIG (JEE Interface Group) came up with a special procedure to normalize marks obtained in Class 12.

The first step in the Normalization Procedure involves conversion of the marks obtained by the candidate in Class 12 into a percentile* by taking into consideration the aggregate marks of the 5 subjects as per specifications by CBSE.

*Percentile can be calculated as follows: All candidates of a particular board receive rankings from highest score to least score (all candidates who cleared the Board examination on the basis of aggregate marks mentioned above)

Percentile score = [(Total no. of candidates who are ranked below the considered candidate)/(Total no. of candidates who cleared the Board examination)]*100

• Let the candidate of interest’s percentile score be called “P”

• Let the candidate of interest’s JEE Main score be called “A0”

• Then, the below mentioned 2 tables will be created.

Table 1:

This table will feature the JEE Main marks listed from highest ranker to last ranker (qualified as per CBSE declaration) on the basis of All India rankings, regardless of which board they have passed out from, following which each candidate will be allocated a percentile. Calculation formula for Percentile is mentioned below:

Percentile Score = [(Total no. of candidates who are ranked below the considered candidate on the basis of JEE Main score according to Table 1)/(Total no. of candidates who are qualified for JEE Main as per Table 1)]*100

Table 2:

This table will feature marks obtained at JEE Main from highest ranker to last ranker (qualified as per CBSE declaration) for each of the different boards (Each list will feature candidates of MH board or ISC or CBSE) and then the percentile allotted to each candidate. Calculation formula for percentile is mentioned below:

Percentile score = [(Total no. of candidates ranked below the considered candidate on the basis of JEE Main score according to Table 2)/(Total no. of candidates who qualified for JEE Main according to Table 2)]*100

• The percentile score denoted by P will be searched in Table 1 and the JEE Main score that corresponds to that particular percentile will be duly noted. Let this be called B1.

• The percentile score denoted by P will be searched in Table 2, and the JEE Main score that corresponds to that particular percentile will be duly noted. Let this be called B2.

• The normalized score of the candidate of interest will be B(Final)=0.5*(B1 + B2)

• Let the overall score be called “C” which is equal to 0.6*A0 + 0.4*B(Final)

This was the normalization procedure in a nutshell.