Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
If the intensity of sound in watts per square metre is I, then the intensity level in decibel (dB) is given by
dB= 10 log(I/I•),
Where the base of logarithm is 10,
I•=10^-12 watt per square metre( roughly the intensity at which audible sound can be heard)
On the decibel scale the pain threshold is 1 watt per square metre and on decibel scale is:
dB= 10 log(1 watt per square metre/10^-12 watt per square metre)
dB= 10 log ( 1/10^-12)= 10* log (10^12)=10*12=120 dB
In the given problem
dB= 10 log ( 2 I/I)= 10* log 2=10*0.3010=3.010dB
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !