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One half of a sphere of radius R & refractive index μ is silvered. A point object is placed in front of the unsilvered portion of the sphere at a distance R from the surface of the sphere. Where will the final image be formed?

7 years ago

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Answers : (1)

										

  in this question


u= distance of object from pole i.e 3R


v = distance of image


f= distance of focal point/


all these distances are taken from pole


therefore a.


u = 3R & R = radius of curvature ; so f= R/2 & R=2f. put this value of R in  u


so u = 6f


thus according to mirror formula


1/v + 1/u = 1/f : put values of u in this equation


 


so 1/v = 1/f - 1/6f


i.e v= 6f/5 & 6f can be written as 3R


so value of v= 3R/5 : hence at this position image will be formed at this distance from pole .

7 years ago

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