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```				   Convex side of a thin concavo-convex lens(μ=1.50) has a radius of curvature of 20cm. The concave surface has a radius of curvature 60cm. The concave part is filled with water of μ=1.33 and the convex side is silvered. What is the effective focal length of the optical system?
```

6 years ago

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```										Dear Abhipsa,
We know the lens makers formula...

Now the given case can be considered as combination of
1. A thin lens of Radius of curvatures given by R1= infinity and R2= -60 cm
and μ = 1.33 refractive index of water
it is a thin lens
thus focal length of this lens is f1= 181.81 cm.
2. A concavo convexlength of  R1= -60 and R2= -20 cm
and  μ = 1.5
thus focal length of it for the case of thin lens is f2=60 cm
and
3. A concave mirror of focal length f3= -R/2 = -10 cm
where R= 20cm
thus resultant focal length becomes 1/f = 1/f1 + 1/f2 + 1/f3
as distances between the lenses are zero
thus resultant focal length is -12.85 cm.
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation.
All the best  !!!

Regards,
```
6 years ago

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