Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Two coherent point sources S1 and S2 vibrating in phase emit light of wavelength λ. The separation between the sources is 2λ. Consider a line passing through S2 and perpendicular to the line S1S2 . What is the smallest distance from S2 where a minimum of intensity occurs?
Dear Sundeep,
See the diagram given below:
Now we know that if I1and I2 are the intensities of the given two coherent sources of light.
then
resultant I = I1 + I2 + 2 √(I1I2) cos δ
δ = phase difference between the two waves coming from the two sources
tan δ = 2λ/y....................1
and also
cos δ = x/2λ.........................2
where x is the path difference between the waves and y is the distance along S2 at which I is minimum
So phase difference must be odd multiples of π
so δ = (2m+1) π
and δ = x * 2π/ λ
From 2 and above equation we get cos θ = (2m+1)/4 where θ is shown in the figure
for first minima
m=0
so cos θ = 1/4
tan θ = √15
and from 1
y = 2λ/√15
is the distance at which we get first minima
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !