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sundeep 93 Grade: 11
        

Two coherent point sources S1 and S2 vibrating in phase emit light of wavelength λ. The separation between the sources is 2λ. Consider a line passing through S2 and perpendicular to the line S1S2 . What is the smallest distance from S2  where a minimum of intensity occurs?

7 years ago

Answers : (1)

Askiitians Expert Bharath-IITD
23 Points
										

Dear Sundeep,


See the diagram given below:


 


5940-1108_8384_Untitled.jpg


Now we know that if I1and I2 are the intensities of the given two coherent sources of light.


then


resultant I = I1 + I2 + 2 √(I1I2) cos δ


δ = phase difference between the two waves coming from the two sources


tan δ = 2λ/y....................1


and also


cos δ = x/2λ.........................2


 where x is the path difference between the waves and y is the distance along S2 at which  I is minimum


So phase difference must be odd multiples of π


so δ = (2m+1) π


and δ = x * 2π/ λ


         From 2 and above equation we get cos θ = (2m+1)/4  where θ  is shown in the figure


for first minima


m=0


so cos θ = 1/4


tan θ = √15


and from 1


y = 2λ/√15


is the distance at which we get first minima  

7 years ago
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