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`        A convexo-convex lens has focal length of f=10 cm.One of lens surfaces having radius of curvature of R=10 cm is coated with silver.Find position of image if object is at distance of 15 cm from lens.Refractive index of lens=1.5.(Ans.-2.14 cm)Please explain.`
6 years ago

SAGAR SINGH - IIT DELHI
879 Points
```										Dear student,
We have the Lens Formula as:
1/f = 1/v – 1/uwhere f= focal lengthv = image distanceu = object distance
There is a relation between radius of curvature and focal length given by the Lens Maker’s Formula.
1/f = (1μ2 – 1) (1/ R1 – 1/R2)where f = focal length1μ2 = μ2/ μ1 = refractive index of the second medium / refractive index of the first mediumR1 = radius of curvature of the first refracting surface of the lensR2 = radius of curvature of the second refracting surface of the lens.

All the best.
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Sagar Singh
B.Tech, IIT Delhi

```
6 years ago
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