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The total energy is given as
E = PE + KE = (1/2)kA2
now,
PE = (1/2)kx2
here
x = A/3
thus,
PE = (1/2)k.(A/3)2
= (1/18)kA2
so,
PE = (1/9).[(1/2)kA2]
or
PE = E/9
and so, kinetic energy
KE = E - PE = E - E/9
KE = (8/9).E
Regards
Arun (askIITians forum expert)
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