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Amit Saxena Grade: upto college level
        Two long strings A and B, each having linear mass density 1.2 × 10-2 kg m-1, are stretched by different tensions 4.8 N and 7.5 N respectively and are kept parallel to each other with their left ends at x = 0. Wave pulses are produced on the strings at the left ends at t = 0 on string A and at t = 20 ms on string B. When and where will the pulse on B overtake that on A?
3 years ago

Answers : (1)

Deepak Patra
askIITians Faculty
474 Points
										Sol. . mA = 1.2 * 10–2 kg/m, TA = 4.8 N

⇒ VA = √T /m = 20 m/s
mB = 1.2 * 10–2 kg/m, TB = 7.5 N
⇒ VB = T /m = 25 m/s
t = 0 in string A
t1 = 0 + 20 ms = 20 * 10–3 = 0.02 sec
In 0.02 sec A has travelled 20 * 0.02 = 0.4 mt
Relative speed between A and B = 25 – 20 = 5 m/s
Time taken for B for overtake A = s/v = 0.4/5 = 0.08 sec
3 years ago
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