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Hrishant Goswami Grade: 10
`        The separation between a node and the next antinode in a vibration air column is 25 cm. If the speed of sound in air is 340 m s-1, find the frequency of vibration of the air column.`
3 years ago

## Answers : (1)

Jitender Pal
365 Points
```										Sol. Here given I base 2 = 0.67 m, l base 1 = 0.2 m, f = 400 Hz
We know that
λ = 2(l base 2 – l base 1) ⇒ λ = 2(62 – 20) = 84 cm = 0.84 m.
So, v = nλ = 0.84 × 400 = 336 m/s
We know from above that,
L base 1 + d = λ/4 ⇒ d = λ/4 – l base 1 = 21 – 20 = 1 cm.

```
3 years ago
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