Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        Light of wavelength 560 nm goes through a pinhole of diameter 0.20 mm and falls on a wall at a distance of 2.00 m. What will be the radius of the central bright spot formed on the wall?`
3 years ago

Jitender Pal
365 Points
```										Sol. For the thin oil film,
d = 1 * 10^–4 cm = 10^–6 m, μ base oil = 1.25 and μ base x = 1.50
λ = 2μd/(n + 1/2) 2 * 10^-6 * 1.25 * 2/2n + 1 = 5 * 10^-6m/2n + 1
⇒ λ = 5000 nm/2n + 1
For the wavelengths in the region (400 nm – 750 nm)
When, n = 3, λ = 5000/2 * 3 + 1 = 5000/7 = 714.3 nm
When, n = 4, λ = 5000/2 * 4 + 1 = 5000/9 = 555.6 nm
When, n = 5, λ = 5000/2 * 5 + 1 = 5000/11 = 454.5 nm

```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Wave Motion

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
Get extra Rs. 413 off
USE CODE: COUPON10
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details
Get extra Rs. 445 off
USE CODE: COUPON10