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`        In Quincke’s experiment, the sound intensity has a minimum value I at a particular position. As the sliding tube is pulled out by a distance of 16.5 mm, the intensity increases to a maximum of 9 I. Take the speed of sound in air to be 330 m s-1. (a) Find the frequency of the sound source. (b) Find the ratio of the amplitudes of the two waves arriving at the detector assuming that it does not change much between the positions of minimum intensity and maximum intensity. `
3 years ago

Jitender Pal
365 Points
```										Sol. a) According to the data
λ/4 = 16.5 mm ⇒ λ = 66 mm = 66 × 10^–6=3 m
⇒ n = V/λ = 330/66 * 10^-3 = 5 kHz.
b) l base minimum = K(A base 1 0 A base 2)^2 = l ⇒ A base 1 – A base 2 = 11
l base minimum = K(A base 1 0 A base 2)^2 = 9 ⇒ A base 1 + A base 2 = 31
So,  A base 1 + A base 2/A base 1 + A base 2 = 3/4 ⇒ A base 1/ A base 2 = 2/1
So, the ratio amplitudes is 2.

```
3 years ago
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