Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        In a standing wave pattern in a vibrating air column, nodes are formed at a distance of 4.0 cm. If the speed of sound in air is 328 m s-1, what is the frequency of the source?`
3 years ago

Kevin Nash
332 Points
```										Sol. Here given that 1 = 50 cm, v = 340 m/s
As it is an open organ pipe, the fundamental frequency f base 1 = (v/21)
= 340/2 * 50 * 10^-2 = 340 Hz.
So, the harmonies are
f base 3 = 3 × 340 = 1020 Hz
f base 5 = 5 × 340 = 1700, f base 6 = 6 × 340 = 2040 Hz
So, the possible frequencies are between 1000 Hz and 2000 Hz are 1020, 1360, 1700.

```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Wave Motion

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details