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`        Consider the situation of the previous problem. If the mirror reflects only 64% of the light energy falling on it, what will be the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen?`
3 years ago

Kevin Nash
332 Points
```										Sol. Given that, the mirror reflects 64% of energy (intensity) of the light.
So, l base 1/l base 2 = 0.64 = 16/25 ⇒ r base 1/r base 2 = 4/5
So, l base max/l base min = (r base 1 + r base 2)^2/( r base 1 - r base 2)^2 = 81: 1.

```
3 years ago
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