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`        An open organ pipe has a length of 5 cm. (a) Find the fundamental frequency of vibration of this pipe. (b) What is the highest harmonic of such a tube that is in the audible range? Speed of sound in air is 340 m s-1 and the audible range is 20-20,000 Hz.`
3 years ago

396 Points
```										Sol. Let the length of the resonating column will be = 1
Here V = 320 m/s
Then the two successive resonance frequencies are (n + 1)/4 l and nv/4 l
Here given (n + 1)v/4 l = 2592 ; λ = nv/4 l = 1944
⇒ (n + 1)v/4 l - nv/4 l = 2592 – 19444 = 548 cm = 25 cm.

```
3 years ago
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