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`        A tuning fork produces 4 beats per second with another tuning fork of frequency 256 Hz. The first one is now loaded with a little wax and the beat frequency is found to increase to 6 per second. What was the original frequency of the tuning fork?`
3 years ago

Jitender Pal
365 Points
```										Sol. Group – I Group – II
Given V = 350 v = 350
λ base 1 = 32 cm λ base 2 = 32.2 cm
= 32 × 10^–2 m = 32.2 × 10^–2 m
So η base 1 = frequency = 1093 Hz η base 2 = 350 / 32.2 × 10^–2 = 1086 Hz
So beat frequency = 1093 – 1086 = 7 Hz.

```
3 years ago
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