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`        A steel wire of mass 4.0 g and length 80 cm is fixed at the two ends. The tension in the wire is 50 N. Find the frequency and wavelength of the fourth harmonic of the fundamental. `
3 years ago

396 Points
```										Sol. m = (4/80) g/m cm = 0.005 kg/m
T = 50 N, I = 80 cm = 0.8 m
V = √(T/ m) = 100 m/s
Fundamental frequency f base 0 = 1/2l√(t/m) = 62.5 Hz
First harmonic= 62.5 Hz
V = f base4 λ base 4 ⇒ λ base 4 = (v/f base 4) =40 cm.

```
3 years ago
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