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```        A pulse travelling on a string is represented by the function
Y = a^3/((x-vt)^2+a^2 ).
Where a = 5 mm and v = 20 cm s-1. Sketch the shape of the string at t = 0, 1 s and 2 s. Take x = 0 in the middle of the string.
```
3 years ago

Deepak Patra
474 Points
```										Sol. The pulse is given by, y = [(a3) / {(x – vt)2 + a2}]
a = 5 mm = 0.5 cm, v = 20 cm/s
At t = 0s, y = a3 / (x2 + a2)
The graph between y and x can be plotted by taking different values of x.
(left as exercise for the student)
similarly, at t = 1 s, y = a3 / {(x – v)2 + a2}
and at t = 2 s, y = a3 / {(x – 2v)2 + a2}

```
3 years ago
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