a particel executing shm has an amplitude of 6cm its acceleration at a distance 2cm from mean position is 8cm .the maximum speed is?

Question

Ashutosh Mohan Sharma · Answer

a= (&omega;^2)*y (&omega;^2)*2= 8 (&omega;^2) =4 so &omega;=2rads per second maxV=A*&omega;= 6*2=12 cm per secpnd

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a particel executing shm has an amplitude of 6cm its acceleration at a distance 2cm from mean position is 8cm .the maximum speed is?

a particel executing shm has an amplitude of 6cm its acceleration at a distance 2cm from mean position is 8cm .the maximum speed is?

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a particel executing shm has an amplitude of 6cm its acceleration at a distance 2cm from mean position is 8cm .the maximum speed is?

a particel executing shm has an amplitude of 6cm its acceleration at a distance 2cm from mean position is 8cm .the maximum speed is?

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