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Simran Bhatia Grade: 11
        A man stands before a large wall at a distance of 50.0 m and claps his hands at regular intervals. Initially, the interval is large. He gradually reduces the interval and fixes it at a value when the echo of a clap merges with the next clap. If he has to clap 10 times during every 3 seconds, find the velocity of sound in air.
3 years ago

Answers : (1)

Kevin Nash
askIITians Faculty
332 Points
										Sol. He has to clap 10 times in 3 seconds.

So time interval between two clap = (3/10 second).
So the time taken go the wall = (3/2 × 10) = 3/20 seconds.
= 333 m/s.
3 years ago
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