Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        A cylindrical metal tube has a length of 50 cm and is open at both ends. Find the frequencies between 1000 Hz and 2000 Hz at which the air column in the tube can resonate. Speed of sound in air is 340 m s-1.`
3 years ago

396 Points
```										Sol. According to the questions
f base 1 first overtone of a closed organ pipe P base 1 = 3v/4l = 3* V/ 4 * 30
f base 2 fundamental frequency of a open organ pipe P base 2 = V/2l base 2
Here given 3V/4 * 30 = V/2l base 2 ⇒ l base 2 = 20 cm
∴length of the pipe P base 2 will be 20 cm

```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Wave Motion

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
Get extra Rs. 413 off
USE CODE: COUPON10
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details
Get extra Rs. 445 off
USE CODE: COUPON10

Post Question