Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        A 200 Hz wave with amplitude 1 mm travels on a long string of linear mass density 6 g m-1 kept under a tension of 60 N. (a) Find the average power transmitted across a given point on the string. (b) Find the total energy associated with the wave in a 2.0 m long portion of the string.`
3 years ago

Jitender Pal
365 Points
```										Sol. . A = 1 mm = 10–3 m, m = 6 g/m = 6 * 10–3 kg/m
T = 60 N, f = 200 Hz
∴ V = √T /m = 100 m/s
a) Paverage = 2π2 mv A2f2 = 0.47 W
b) Length of the string is 2 m. So, t = 2/100 = 0.02 sec.
Energy = 2π2 mvf2A2t = 9.46 mJ.

```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Wave Motion

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
Get extra Rs. 413 off
USE CODE: COUPON10
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details
Get extra Rs. 445 off
USE CODE: COUPON10