Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        A tuning fork while vibrating with an air column at 51 degree celcius produces 4 beats and the same tuning fork produces 1 beats at 16 degree celcius. Find Frequency Of Tuning Fork. Ans 50Hz`
7 years ago

Ramesh V
70 Points
```										when temp. decreases, speed of sound in air decreases, since no. of beats per second is less at lower tempertaure we coclude that frequency of aircolumn is higher than freq. of tuning fork.
let v be freq. of tuning fork, then at 51 degrees frq. of air column will be (n+4) where n is freq. of tuning fork
at 16 degrees , frewq. of air column will be (n+1)
v51/v16 = (n+4)*k / (n+1)*k
(n+4)/(n+1) = (273+51)1/2 / (273+16)1/2
on solving ofr n , we'll get n = 50 Hz
--
regards
Ramesh
```
7 years ago
Nehal Wani
21 Points
```										Thank You very Much Sir.
```
7 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Wave Motion

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details