0

Guest

Courses New

A tuning fork of frequency 328 hz is moved towards a wal at a speed of 2 m/s .an observer standing on the same side as the fork hears two sounds one directly from the fork and the other reflectd from the wal.number of beats per second is (velocity of sound in air is 33 m/s)

 


A tuning fork of frequency 328 hz is moved towards a wal at a speed of 2 m/s .an observer standing on the same side as the fork hears two sounds one directly from the fork and the other reflectd from the wal.number of beats per second is (velocity of sound in air is 33
m/s)

Grade:12th Pass

1 Answers

Ashish Kumar
askIITians Faculty 32 Points
10 years ago
The apparent frequency observed of the sound directly coming from the tuning fork ,
f1=v/(v-Us) f, As the source is moving away from the observer Us will be negative.
f1= 330/(330 + 2) 328 = 326.02 Hz
The apparent frequency received at the wall will be F=v/(v -Us), for this the Us will be positive as it is moving towards the wall. therefore, F = 330 / (330 - 2) 328 = 330 Hz.
Now the wall will reflect this wave at frequency F and therefore act as a soure for the observer.As there is no relative motion between the source(wall) and the observer the freq osbserved for the reflected sound wave will be F=330 Hz
frequency of beats = F - f1 = 330 - 326.02 = 3.98 Hz







169-2062_signature1.GIF

Think You Can Provide A Better Answer ?

Other Related Questions on Wave Motion

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More