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`        An engine whestles at a frequency of 256Hz moves towards  a wall with a velocity of 50m/s. How many number of beats will be sounded to the engine?`
8 years ago

devashish trivedi
8 Points
```										Doppler's fomula is
n' = n (v -vo)/(v-vs)
where n' = apprant frequency
n = original frequency
v = spped of sound in air that is 330 m/s
vo = speed of observer
vs = speed of the source
Here n = 256 hz vo = 0 vs = 50m/s pluging in the values we will get n = 497 hz
now with this frequency the sond will reflect from the wall so the source will be stationary
we will again use the same formula
n" = n (v -vo)/(v-vs)
now vo = 50m/s , vs = 0 and v =330m/s n" = frequency heard by the observer
now pluging in the values we will have
n" = 497(330 - 50)/(330 - 0)
= 497x 280/330
= 422hz so the no of beats heard by the observer is n" - n = 422 - 256=      166 beats per second
```
8 years ago
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