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`        The potential energy of a particle executing SHM alon x-axis is U=U0(1-cosax).What is the frequency of oscillation? `
6 years ago

SAGAR SINGH - IIT DELHI
879 Points
```										Dear student
U=U0(1-cosax)
Force=-dU/dx=-aU0sinax=-w^2 (x)
from here you can easliy calculate frequency on comparing the two..

All the best.
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Sagar Singh
B.Tech, IIT Delhi

```
6 years ago
510 Points
```										U = U0(1-cosax)
F = -dU/dx = -Uoasinax
for small x , sinax is small or sinax = ax
F = -U0a2x
a = -Uoa2x/m                              (a = -w2x)
-w2x = -Uoa2x/m
w = (Uoa2/m)1/2
```
6 years ago
510 Points
```										U = U0(1-cosax)
F = -dU/dx = -Uoasinax
for small x , sinax is small or sinax = ax
F = -U0a2x
a = -Uoa2x/m                              (a = -w2x)
-w2x = -Uoa2x/m
w = (Uoa2/m)1/2

```
6 years ago
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