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rajan jha Grade: 12
        

A simple pendulum of length l and mass m is suspended in a car that is moving with constant velocity v around a circle of radius r. Find its time period and equilibrium position?pls post fast

6 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

car is moving along the circle so centripital force is acting on the car but bob experiences a centrifugal force ....


let the angle made with verticle is @ & T is the tension in the string  then


Tcos@ = mg


Tsin@ = mv2/r


tan@ = v2/rg  


bob is at equilibrium at @ = tan-1 (v2/g)


now


       net force acting on bob = (mv2r) i + (mg) j


                                    a = v2/r i+ g j


               magnitude of a= [ (v2/r)2 + g2 ]


T = 2pi(L/geff)


  =2pi { L/[(v2/r)2 +g2] }1/2

6 years ago
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