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`        A simple pendulum of length l and mass m is suspended in a car that is moving with constant velocity v around a circle of radius r. Find its time period and equilibrium position?pls post fast`
6 years ago

510 Points
```										car is moving along the circle so centripital force is acting on the car but bob experiences a centrifugal force ....
let the angle made with verticle is @ & T is the tension in the string  then
Tcos@ = mg
Tsin@ = mv2/r
tan@ = v2/rg
bob is at equilibrium at @ = tan-1 (v2/g)
now
net force acting on bob = (mv2r) i + (mg) j
a = v2/r i+ g j
magnitude of a= [ (v2/r)2 + g2 ]
T = 2pi(L/geff)
=2pi { L/[(v2/r)2 +g2] }1/2
```
6 years ago
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