Find the vector equation of the plane through the points (2, 1, –1) and (–1, 3, 4) and perpendicular to the plane x – 2y + 4z = 10.

Question

Sourabh Singh · Answer

You need to consider normal to a plane as (a,b,c). You have 2 coplanar vectors and normal to the plane with the help of which you can find the value of a, b ,c .

Smruthi · Answer

Sir, I tried to do it............but got stuck up in the middle........... can u please solve it......!!!!

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Find the vector equation of the plane through the points (2, 1, –1) and (–1, 3, 4) and perpendicular to the plane x – 2y + 4z = 10.

Find the vector equation of the plane through the points (2, 1, –1) and (–1, 3, 4) and perpendicular to the plane x – 2y + 4z = 10.

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Find the vector equation of the plane through the points (2, 1, –1) and (–1, 3, 4) and perpendicular to the plane x – 2y + 4z = 10.

Find the vector equation of the plane through the points (2, 1, –1) and (–1, 3, 4) and perpendicular to the plane x – 2y + 4z = 10.

2 Answers

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Other Related Questions on Vectors

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