A ray of light traveling in a direction 1 /2 (i^ + 3j^) is incident on a plane mirror. After reflection it travels along the direction of 1/2 (i^ - 3j^). Calculate the angle of incidence.

Question

sonika p · Answer

by drawing the vectors we can see that, light ray gets reflected through x-axis thus x-axis is the normal. incident ray,a = ½ (i+3j) n = i angle between them gives angle of incidence cos theta = (a.n)/(|a||n|) = (1/2) / ((1/2*)root10) cos theta = 1/root10 theta = 79.5 0

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A ray of light traveling in a direction 1 /2 (i^ + 3j^) is incident on a plane mirror. After reflection it travels along the direction of 1/2 (i^ - 3j^). Calculate the angle of incidence.

A ray of light traveling in a direction 1 /2 (i^ + 3j^) is incident on a plane mirror. After reflection it travels along the direction of 1/2 (i^ - 3j^). Calculate the angle of incidence.

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A ray of light traveling in a direction 1 /2 (i^ + 3j^) is incident on a plane mirror. After reflection it travels along the direction of 1/2 (i^ - 3j^). Calculate the angle of incidence.

A ray of light traveling in a direction 1 /2 (i^ + 3j^) is incident on a plane mirror. After reflection it travels along the direction of 1/2 (i^ - 3j^). Calculate the angle of incidence.

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