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`        If  the ai+j+k,i+bj+k and i+j+ck are coplanar then the value of 1/1-a+1/1-b+1/1-c= `
7 years ago

147 Points
```										Dear pallavi
If  the ai+j+k,i+bj+k and i+j+ck are coplanar then  we can write
ai+j+k = x(i+bj+k)  + y( i+j+ck )
so
a= x+ y ...........1
1= bx +y ...........2
1= x +cy ............3
(2) -(1)           1-a  =-x(1-b)
(3) -(1)           1-a  = -y(1-c)
so   1-a  =-x(1-b)  =-y(1-c)
or  1/1-a  +   1/1-b   +   1/1-c
= 1/1-a     - x/1-a     -  y/1-a
=1/1-a [1-(x+y)]
= 1/1-a [1-a]
=1
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.
```
7 years ago
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