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pallavi pradeep bhardwaj Grade: 12
        

If  the ai+j+k,i+bj+k and i+j+ck are coplanar then the value of 1/1-a+1/1-b+1/1-c= 

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear pallavi


If  the ai+j+k,i+bj+k and i+j+ck are coplanar then  we can write


ai+j+k = x(i+bj+k)  + y( i+j+ck )


so


 a= x+ y ...........1


1= bx +y ...........2


1= x +cy ............3


(2) -(1)           1-a  =-x(1-b)


(3) -(1)           1-a  = -y(1-c)


  so   1-a  =-x(1-b)  =-y(1-c)


 or  1/1-a  +   1/1-b   +   1/1-c  


 = 1/1-a     - x/1-a     -  y/1-a


=1/1-a [1-(x+y)]


= 1/1-a [1-a]


 =1


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Badiuddin

7 years ago
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