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If a=i-j and b=i+k then a unit vector coplanar with a and b and perpendicular to a is
Dear pallavi
you can take any vector in plane of two given vector
r =xa +yb
=x(i-j) +y (i+k)
=i(x+y) -xj +yk
if it is perpendicular to a then
r.a=o
{i(x+y) -xj +yk}.(i-j)=0
2x+y=0
so r will become r= -x[i+j +2k]
if it is a unit vecttor then ( x2 + x2 +4x2)1/2=1
x= ±1/√6
so r= ±1/√6[i +j+2k]
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