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PRADEEP KUMAR Grade:
        1.) A rigid body is rotating at 2.5 rad/sec about an axis AB,where A and B are the point (1,-2,1) and (3,-4,2).

Find the velocity of the particle P of the body at the point(5,-1,-1).

6 years ago

Answers : (1)

Priyansh Bajaj AskiitiansExpert-IITD
30 Points
										

Dear Pradeep,


Solution:-  AB = B -A ; where A and B are vector A and  vector B respectively.


AB = (3i -4j + 2k) - (i -2j +k) = 2i -2j + k


|AB| = 3


velocity of particle P = ωr; where ω = 2.5 and 'r' is the radius, which is the distance of P from AB axis.


i.e., r = perpendicular distance of point P from line AB


      r = | {AP - [(AP .AB)/ |AB|] AB} |


   AP = P - A = (5i-j-k) - (i -2j +k) = 4i +j -2k


AP. AB = 8- 2 -2 = 4


  r = | {(4i +j -2k) - [4/3] (2i -2j + k)} |


  r = | {(4i +j -2k)


[ANS]



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Priyansh Bajaj

6 years ago
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