MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Menu
Aman Sagar Grade: 11
        

The  height reached by a particle in time thrown upward with a speed u is given by  h=ut - (1/2)g(t*t) , where g is a constant .   


Find the time taken in reaching the maximum height.

6 years ago

Answers : (1)

Prabodh Yadav
31 Points
										

differentiate this eqn(h) wrt t,i.e.,find dh/dt to get the general expression for velocity(varying with t).Now at max height dh/dt=0 therefore put dh/dt=0 in dh/dt.solve and get t!!


dh/dt=u-gt


now at max height


dh/dt=0


thus,u-gt=0


=>t=u/g

6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details
Get extra R 13,000 off
USE CODE: JEE1
  • Statistics and Probability
  • OFFERED PRICE: R 600
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details