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The height reached by a particle in time thrown upward with a speed u is given by h=ut - (1/2)g(t*t) , where g is a constant .
Find the time taken in reaching the maximum height.
differentiate this eqn(h) wrt t,i.e.,find dh/dt to get the general expression for velocity(varying with t).Now at max height dh/dt=0 therefore put dh/dt=0 in dh/dt.solve and get t!!
dh/dt=u-gt
now at max height
dh/dt=0
thus,u-gt=0
=>t=u/g
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