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`        two vectors A and B have magnitude 2 and 1 respectively. if the angle between A and B is 60 degree then the vector A/2-B is `
7 years ago

Sona Srivastava
38 Points
```										A/2-B = (A/2) + (-B)
R = √((A/2) 2 +B2 + 2(A/2)BCos(120))
A/2 = 1
B = 1Cos120 = -1/2
R = 1 AT AN ANGLE OF = TAN-1 ((ASin60)/(B-ACos60)) AT AN ANGLE OF 90° FROM (-B) OR B
```
7 years ago
25 Points
```										Dear Naba
Given |A|=2 |B|=1
angle between A and B =60
Now call vector A/2 as C
|C|=|A|/2=1
and angle between B and C will be the same as that between A and B
|C-B|=√|c|2 + |B|2 -2|C||B|cos 60°
=√1+1-1=1
As it is clear from the diagram C-B will be along angle bisector of -B and C so angle between C and A=60°
ALL THE BEST
Abhinav Batra

```
7 years ago
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