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tanA+2tan2A+4tan4A+8tan8A+16tan16A+32tan32A is equal to

tanA+2tan2A+4tan4A+8tan8A+16tan16A+32tan32A is equal to

Grade:12th pass

1 Answers

Ritesh Khatri
76 Points
6 years ago
cotA – tanA = 2cot2A
tanA = cotA – 2cot2A
2tan2A = 2cot2A – 4cot4A
4tan4A = 4cot4A  – 8cot8A
8tan8A = 8cot8A – 16cot16A
16tan16A = 16cot16A – 32cot32A
32tan32A = 32cot32A – 64cot64A
 
on Adding all equations we get 
LHS = required term
RHS = cotA – 64cot64A

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