sin A = 1/2 and cos A = 1/3.
Hence, A = π/ 6 and 0
So, A = π/ 6 and cos^-1(0) > B >cos^-1(1/2)
how?????

Question

sin A = 1/2 and cos A = 1/3. Hence, A = π/ 6 and 0 So, A = π/ 6 and cos -1 (0) > B >cos -1 (1/2) how?????

Deepak Kumar Shringi · Answer

your question is wrong either sinA=1/2 or cosA=1/3 because if sinA=1/2 for sure cosA=root 3/2 (positive or negative) check your question and respost it

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sin A = 1/2 and cos A = 1/3. Hence, A = π/ 6 and 0 So, A = π/ 6 and cos -1 (0) > B >cos -1 (1/2) how?????

sin A = 1/2 and cos A = 1/3.
Hence, A = π/ 6 and 0
So, A = π/ 6 and cos^-1(0) > B >cos^-1(1/2)
how?????

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sin A = 1/2 and cos A = 1/3. Hence, A = π/ 6 and 0 So, A = π/ 6 and cos -1 (0) > B >cos -1 (1/2) how?????

sin A = 1/2 and cos A = 1/3.Hence, A = π/ 6 and 0 So, A = π/ 6 and cos-1(0) > B >cos-1(1/2) how?????

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sin A = 1/2 and cos A = 1/3.
Hence, A = π/ 6 and 0
So, A = π/ 6 and cos^-1(0) > B >cos^-1(1/2)
how?????