0

Guest

Courses New

If x=5+2√6 and tany=1/2(√x+1/√x) then find the value of sec^2y+sin^2y.

If x=5+2√6 and tany=1/2(√x+1/√x) then find the value of sec^2y+sin^2y.

Grade:12th pass

1 Answers

Lab Bhattacharjee
121 Points
8 years ago
x=5+2\sqrt6=(\sqrt3+\sqrt2)^2 \implies \sqrt x=\sqrt3+\sqrt2, \dfrac1{\sqrt x}=\cdots=\sqrt3-\sqrt2 \\ \text{ Now use } \sin^2y=\dfrac1{1+\cot^2y}=\dfrac{\tan^2y}{\tan^2y+1} \\ \text{and } \sec^2y=\tan^2y+1

Think You Can Provide A Better Answer ?

Other Related Questions on Trigonometry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More