if tanx/tany=1+cos 2 x/1+sin 2 x show that sin(3x+y)=7sin(x-y).

Question

Vijay Mukati · Answer

Hint: convert tanX and tanY into corresponding sin/cos form. Then apply componendo and dividendo.use the formulas of 2 sinAcosB and simplyfy it. Thanks.

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if tanx/tany=1+cos 2 x/1+sin 2 x show that sin(3x+y)=7sin(x-y).

if tanx/tany=1+cos²x/1+sin²x show that sin(3x+y)=7sin(x-y).

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if tanx/tany=1+cos 2 x/1+sin 2 x show that sin(3x+y)=7sin(x-y).

if tanx/tany=1+cos2x/1+sin2x show that sin(3x+y)=7sin(x-y).

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if tanx/tany=1+cos²x/1+sin²x show that sin(3x+y)=7sin(x-y).