MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
AYESHA Grade: 11
        
  1. if A and B are acute angles and sin A = 1/5√2 and tan B = 1/3 then A+2B=?
2 years ago

Answers : (1)

Akshay
185 Points
										
 
Sin A= 1/5*rt(2), cos A=7/5*rt(2);        cos A= sqrt(1-sin2A)
Tan B= 1/3, sin B= 1/rt(10), cos B= 3/rt(10);  cos B= sqrt(1-sin2B)
sin (2B) = 2sinBcosB = 3/5, cos(2B) = 4/5;
Sin(A+2B) = sin(A)*cos(2B) + cos(A)*sin(2B);
= (4+21) /(25.rt(2))
=1/rt(2);
A+2B = 45 deg
2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details