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in a triangle ABC, (a+b+c)(b+c-a)=Λbc if......(condition)?
Dear nishant
(a+b+c)(b+c-a)=abc
((b+c)+a)((b+c)-a)=abc
(b+c)2 -a2 =abc
b2 +c2 +2bc -a2 =abc
b2 +c2 -a2 =abc -2bc
(b2 +c2 -a2)/2bc =a/2 - 1
cosA =a/2 - 1
since -1< cosA <1
so -1< a/2 - 1 <1
0< a/2<2
0<a<4
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