MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Sonam Ghatode Grade: 11
        


tan nA= nC1 tan A-nC3 tan3A + nC5 tan5A …/1- nC2 tan2A+ nC4 tan4A-…


 


7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear Sonam


we know 


cosnA + iSin nA =(cosA +isinA)n


open bracket with the help of binomial


cosnA + iSin nA =(cosA +isinA)n = cosnA + nC1 cosn-1A(isinA) + nC2cosn-2A(isinA)2 +.......


                             = (cosnA  - nC2cosn-2A(sinA)2 +.... ) + i(nC1 cosn-1A(sinA) - nC3 cosn-3A(sinA)3 .......)


 


compair Real  part


 Cos nA = (cosnA  - nC2cosn-2A(sinA)2 +.... )


              =cosnA(1-nC2 tan2A-nC4 tan3A -…)............................1


 


compair imaginery part


 Sin nA = (nC1 cosn-1A(sinA) - nC3 cosn-3A(sinA)3 .......)


              =cosnA(nC1 tanA - nC3(tanA)3 .......  ...........)  .............2


devide equatin 2 from 1


tan nA = nC1 tan A-nC3 tan3A + nC5 tan5A …/1- nC2 tan2A+ nC4 tan4A-…




Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you
the answer and detailed  solution very  quickly.

 We are all IITians and here to help you in your IIT JEE preparation.

All the best.
 
Regards,
Askiitians Experts
Badiuddin

7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details
Get extra Rs. 6,837 off
USE CODE: JYOTI
Get extra Rs. 273 off
USE CODE: JYOTI

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details